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Using the square root method... 5x^2+35=0
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you mean completing the square?
or its kin
it says solve by the square root method
5(x^2+7) = 0, there is no real number that will do this
I know, it will end up with i in the answer
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x^2 + 7 = 0 x^2 = -7 x = +- i sqrt(7)
Thanks
i got no idea if that the "square root" method or not tho
Nope, I know you have to make it 5x^2=-35 and then I dont really know how to proceed. Thanks
divide off the 5
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and you get to x^2 = -7
When do you take the sq rt from each side?
when you get x^2 all alone in order to operate on it
the sqrt and the ^2 cancel each other out
if it (5x)^2 , then you can do it as is; but the way you wrote it, you only have an x^2
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