Question

find the limit.
lim approaches +infinity at sin^-1((3x)/(5-6x))

Answer 1

\[\lim_{x \rightarrow \infty}\frac{3x}{5-6x}=\frac{3}{-6}=\frac{-1}{2}\]

Answer 2

actually mik-wind was more correct
i think f(x)=sin(x) is defined on (-pi,pi) and its range is (-1,1)

so
f(x)=sin^{-1}(x) has domain (-1,1) and range (-pi,pi)

Answer 3

it is \[\frac{-\pi}{6}\]

Answer 4

can someone explain to me how the answer is -pi/6