Question

need help on problem number 52 on the attachment

Answer 1

a)
g(x)=x^(2/3)
g'(x)= 2/3x^(-1/3)
g'(0) = 0

It does not exist.

Answer 2

b)
When g'(a) is not equal to zero.
g'(a)= (2/3)a^(-1/3)

Answer 3

g'(0) does not exist since
\[g'(x)=\frac{2}{3x^\frac{1}{3}}\]

Answer 4

a) involves dividing by 0, so it its not allowed

Answer 5

how did you get zero, did plug that into x

Answer 6

after taking the derivative?

Answer 7

yes, look at myininaya's post

Answer 8

can clarify for me, so more about part b solution

Answer 9

if you plug in 0 you get 0 on the bottom and like wind said this not allowed
so g'(0) does not exist

Answer 10

oops! I mean clarify part some for me, please!

Answer 11

since g(0)=0 exists and g'(0) does not exist=> sharp turn=> vertical tangent

Answer 12

sharp turn means the slope makes a sudden change