Ask your own question, for FREE!
Mathematics 17 Online
OpenStudy (anonymous):

Calculate sin0?

OpenStudy (anonymous):

OpenStudy (anonymous):

triangle wont help here will it?

OpenStudy (anonymous):

mmm idk

OpenStudy (anonymous):

sin(0) is 0

OpenStudy (anonymous):

look at unit circle on the last page of the cheat sheet attached. find 0. first coordinate is cosine, second is sine

OpenStudy (anonymous):

you will see that on the unit circle you are right at (1,0) so \[\cos(0)=1, \sin(0)=0\] should memorize these they are very common

OpenStudy (anonymous):

help

OpenStudy (anonymous):

what do you need?

myininaya (myininaya):

oh i don't think he means that to be zero lol

myininaya (myininaya):

i think he wants \[\sin(\theta)\]

myininaya (myininaya):

\[\sin(\theta)=\frac{opposite}{hyp}=\frac{oppsite}{12}\] so we can find the oppsite side of theta by using the Pythagorean thm solve this for opp: \[opp^2+10^2=12^2\]

myininaya (myininaya):

\[opp^2+100=144 => opp^2=144-100 => opp^2=44 => opp=\sqrt{44}=2\sqrt{11}\]

myininaya (myininaya):

\[\sin(\theta)=\frac{2 \sqrt{11}}{12}\]

OpenStudy (anonymous):

what about the cos oppo

myininaya (myininaya):

\[\cos(\theta)=\frac{adjacent}{hyp}=\frac{10}{12}=\frac{5}{6}\]

OpenStudy (anonymous):

what about tan???

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!