Find an equation of the line that satisfies the given conditions.
Through
(−1, −3);
perpendicular to the line
2x + 7y + 8 = 0

Question

Find an equation of the line that satisfies the given conditions.
Through 
(−1, −3);
  perpendicular to the line 
2x + 7y + 8 = 0

anonymous · Answer

It's incorrect

mimi_x3 · Answer

Hm whats the correct answer then so i can work it out

anonymous · Answer

IDK... i'm trying to figure it out also.

anonymous · Answer

I got 7x-3y+1=0, but that didn't work.

mimi_x3 · Answer

my bad i forgot that its perpendicular 
m = 7/2 

y = mx + b
-3 = 7/2(-1) + b
-3 = -7/2 + b
b = 2 

y = 7/2x + 2

Is it right now ?

mimi_x3 · Answer

y = 7/2x + 1/2 my bad

anonymous · Answer

In a practice problem they show, the answer ='s to 0

mimi_x3 · Answer

oh in general form ?

anonymous · Answer

Yes

anonymous · Answer

I get to y-(-3)=7/2 (x-(-1))  Then I'm lost on what to do.

anonymous · Answer

using the y-y1=m(x-x1) formula

mimi_x3 · Answer

well, i got 2x - 7y - 23 = 0
Not sure if im right though since im not good at these types of questions

anonymous · Answer

No :(

mimi_x3 · Answer

7x - 2y - 7 = 0

anonymous · Answer

y-(-3) = 7/2 (x-(-1)) ->

2y-7x-1=0