Question

7/ radical 3x = radical (x-4)

Answer 1

\[7\div \sqrt{3x} + \sqrt{x-4}\]

Answer 2

It's a PLUS!! Sorry!

Answer 3

\[\frac{7}{\sqrt{3x}}+ \sqrt{x-4}\]

Answer 4

This is what I got when I multiplied by the conjugate - how close am I?

\[7\sqrt{3x}- 7\sqrt{x-4}\div2x-4\]

Answer 5

I suppose they want you to get rid of the square root in the denominator

Answer 6

yes that is correct

Answer 7

I don't think we want to do a conjugate

Answer 8

Um....you need someone to go over this with you in detail.

Answer 9

I understand that, but I have no one until after the assignment is due - zero period 7am tomorrow! Any help is appreciated!

Answer 10

I'd love to help you out but I charge a fee for personal tutoring

Answer 11

When you have a fraction, and the denominator is a square root, multiply top and bottom by the square root.

Answer 12

if you have a fraction, and the bottom is a square root PLUS a number, multiply the top and bottom by the conjugate.

Answer 13

Thanks, but I don't have any money, and my parents are on a single income. I will do my best to understand what information is hared wuith me at this time.

Answer 14

@phi
That's what I did, but I'm not sure the mechanics are all there

Answer 15

How many questions do you have?

Answer 16

That's how I ended up with the radicals in the numerator. basically a 7 infromnt of each portion of the equations conjugate.

Answer 17

@ hero
This is my last one!

Answer 18

Just to make sure I understand the problem is it
\[\frac{7}{\sqrt{3x}}+ \sqrt{x-4}\]

Answer 19

or is it
\[\frac{7+ \sqrt{x-4}}{\sqrt{3x}}\]

Answer 20

@ phi

no the x-4 under the radical is attached to the radical 3x - they are BOTH below the division bar

Answer 21

\[\frac{7}{\sqrt{3x}+ \sqrt{x-4}}\]

Answer 22

YES!!!

Answer 23

How do you do that? I can not figure this thing out!

Answer 24

It's tough answering the question when I'm doing the wrong one!

Answer 25

lol, wow! Phi great job clarifying

Answer 26

so you do use a conjugate

Answer 27

so what did you get for the bottom?

Answer 28

@ jenn:

Next time, write 7 OVER (sqrt{3x} + sqrt{x - 4})

Answer 29

i got 2x-4 fpr the denominator, and \[7\sqrt{3} - 7\sqrt{x-4}\] for the numerator

Answer 30

@hero
Thanks!

Answer 31

am I close?

Answer 32

should be 3x - (x -4)= 3x-x +4 = 2x+4

Answer 33

top looks good assuming there is an x in the first square root with the 3

Answer 34

for the denominator? - Yes I accidentally forgot the x on the computer, but it's on my paper!

Answer 35

numerator

Answer 36

Yes - Thanks!
I have log questions next! Any interest in helping? I will post them on the other side!

Answer 37

Until you stump me

Answer 38

You are so awesome! I posted it already - give it a look and let me know where to start!