hi everyone! i have a question......
hello izzy!
and we have it's answer.
^^
Thanks, everyone, glad i got your attention okay so i have a piecewise fucntion of \[f(x)=\left\{ x+1, x <-2\right\} and \left\{3x, x \ge -2\right\}\] how do i find the: domain Range Increasing decreasing x intercept y intercept continuous one-to-one boundedness Maximum and minimum And both sides of the end behaviors ya this is the only homework problem that i am having trouble with, i have tried to look on google, and nothing i know how to do the absolute value ones and the linear ones, but piece wise are hard becuase they are of different graphing patterns.
hello?
\[f(x) = \left\{\begin{array}{rcc} x + 1 & \text{if} & x < -2 \\ 3x& \text{if} & x \geq -2 \end{array} \right. \]
ya that's it, i don't know how to do that
domain all real numbers because it is defined for all real numbers
but what is the domain
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i know the domain has to do with infinity
domain is anything. all real numbers
no domain just means what possible inputs are there. you can evaluate this at any number
so how would you write that in mathmatical form ?
\[(-\infty, \infty)\] as an interval. maybe that is what you meant by "infinity"
ya! is that the same with range?
range is also all real numbers \[(-\infty, \infty)\] be
OH
because you see it goes all along the y axis. doesn't skip anything
oh ya that's true
it is always increasing. it is never decreasing.
well that is not right. it is not increasing at -2
wait why?
isn't the other one going downword tho?
so answer to "increasing" is \[(-\infty, -2)\cup (2,\infty)\]
not as we read from left to right
oh
increasing / decreasing means as we read from left to right aka as x increases.
so is it as x increases y increases?
otherwise it has no meaning. like asking do the stairs go up or down. depending on which way you are walking! but we walk from right to left
yes, as x increases, so does y
ohhh
x intercept is (0,0) y intercept is (0,0) you see it from the picture
it is continuous everywhere except at \[x=-2\] because it has a jump there
wiat but what about the other one with the +1
it is not one to one because does not pass the horizontal line test
the other one is \[x+1\] but that is only for \[x<-2\]
so it never crosses the x - axis or the y - axis. make sure you look at the picture i drew. you can see it from there
OH
okay okay, i get it
it is not bounded, and it has no max or min
what you do when you see these is draw the two pictures, in this case two lines, one to the left and the other to the right
gotta run
okay
thanks
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