Question

Solve the following equation analytically.
2 log7(x) = log7(2) + log7(2x + 16)

Answer 1

\[\log_7(x^2)=\log_7(2(2x+16))\]
\[x^2=4x+32\]
\[x^2-4x-32=0\]
\[(x-8)(x+4)=0\]
\[x=8\] forget about
\[x=-4\] because you cannot take the log of a negative number