Question

f(u)= 4u/(u^4+3), g(x) = 48x^2+x+1. find dy/dx of f(g(x)) at x=0

Answer 1

lol i dont really know how to do it without plugging g in for u

Answer 2

omg lol it is

Answer 3

nope , read it wrong

Answer 4

no it is i just submitted 0 and it was right

Answer 5

lol

Answer 6

\[\frac{d}{dx}f(g(x))=f'(g(x))*g'(x)\]

Answer 7

lol ty :)

Answer 8

g(0)=1
g'(0)=1
so find f'(u)
when u =1
when u solve it u get
(4*4-4*4)/(4^2)=0

Answer 9

haha alright ty for the explanation

Answer 10

no prob