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Mathematics 18 Online
OpenStudy (anonymous):

can someone help me to prove that the dimensions of the electric field are: MLT^(-2)Q^(-1)

OpenStudy (anonymous):

first you find the dimension in physics and then you find the formula

OpenStudy (anonymous):

but I dunno how to. Can you teach me how, please?

OpenStudy (anonymous):

M = mass L= length T= time but Q = i dunno

OpenStudy (anonymous):

maybe charge

OpenStudy (anonymous):

MLT^(-2)Q^(-1) that could be? Mass(kg)L(meter)T(sec)^(-2)Q^(-1)(charge=C=coulomb) =kg m /(sec^2 C) ahmm, i think Electric field E = volt/meter =(joules/coulomb)/meter =j/(C m)

OpenStudy (anonymous):

yeay

OpenStudy (anonymous):

well good luck emunrad....

OpenStudy (anonymous):

Thanks guys

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