Question

find an equation of the line
through (-2,-6);parallel to 3x+2y=5

Answer 1

parallel=same slope

y=mx+b, m=-3/2 , (-2,-6)
-6=-3/2(-2)+b
-6=3+b
-6-3=b
-9=b

so the equation is y=-3/2x-9

Answer 2

let required line is 3x+2y=k
since line is passing through point (-2,-6) ..hence
-6-12=k
k=-18

hence required line will be 3x+2y=-18
3x+2y+18=0

Answer 3

or yes you can say this is an correct answer but if if you want in the simplest form and in the form y=mx+b then its y=-3/2x-9

Answer 4

i still dont understand how to do it though, sorry math doesn't come easy

Answer 5

oh so you want steps okay sure!! :)

Answer 6

well i actually gave steps i will just explain every step i did ok?

Answer 7

okay

Answer 8

ok, i guess you know that parallel lines have equal slopes

and you are given an equation or a line which is 3x+2y=5 now put that in the form y=mx+b do get the slope.. (and remember m is the slope)

2y=-3x+5
y= -3/2x+5/2

so u have -3/2 as a slope..

now you have slope whats left? THE Y-INTERCEPT!

you get it by the points you are given which is (-2,-6) now you all you have to is substitute these points (-2 is x and -6 is y ) in the form y=mx+b

y=mx+b (y=-6 , x=-2 , m=-3/2) u have to find B
-6=-3/2(-2)+b
-6=3+b
-6-3=b
-9=b

so we found the y-intercept which is B (-9)

and we found the slope which is m (-3/2)

now we can form an equation..

y=-3/2x-9


im sorryyyy... im just not that good in explaining.. i hope you get some of what i just wrote! :)

tell me if you have an question.. will be my pleasure answering it!! =)

Answer 9

thanks your awesome

Answer 10

yaay! jk , im gllaaddddd i could heelpp!!! =)