Question

Number Relation Problem. The sum of the digits of a two-digit number is 13.If the digits are reversed, the resulting number is 9 less than the original number. What is the original number?

Answer 1

x+y=13
10x+y=10y+x+9
9x=9y+9
x=y+1

2y+1 =13
y=6
x+7

Answer 2

x=7 that is

Answer 3

this is a final answers

Answer 4

The number is \(76\).

Answer 5

Consider the number to be of the form XY, where x and y are both numbers between 0 and 9. The number when reversed is 9 less than the original number implies that \(x>y\). So, we will be left with the following choices for the number: \(94, 85\) or \(76\).
Find the difference between each number and its reverse, and you will find that that \(76-67=9\).

Answer 6

cant you solve the problem

Answer 7

I just did!! The original number is \(76\).

Answer 8

It's a two-digit number, the sum of the digits \(7+6\) is \(13\) and .If the digits are reversed, the resulting number \(67\) is 9 less than the original number \(76\).

Answer 9

I believe you made a mistake somewhere lalaly :)
Let the original number be \(10x+y=10x+13-x=9x+13\)
then the reversed number is \(10y+x=10(13-x)+x=130-9x\)
And since the original number is 9 greater than the reversed one, we have this equation \(9x+13=130-9x+9 \implies x=7\). But \(y=13-7=6\). And therefore the original number is \(76\).
Did I make a mistake somewhere?!