Question

Duncan knows that it takes 36400 cal of energy to heat a pint of water from room temperature to boiling. However, Duncan has prepared ramen noodles so many times he does not need to measure the water carefully. If he happens to heat 0.600 pint of room-temperature water, how many kilojoules of heat energy will have been absorbed by the water at the moment it begins to boil?

Answer 1

1 pint --> 36400 cal to boil from room temp
so 0.600 pints --> \[(0.600 \times 36400)=21840 \]
1 cal = 4.184 joules

Therefore, 21840 cal = (21840 * 4.184) joules = 91378.56 joules = 91 kJ

SO, 0.600 pints require 91kJ to boil from rtp.

Answer 2

its a chem question btw x)