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given a binomial distribution with n = 20 and p = 0.26, would the normal distribution provide a reasonable approximation? why or why not?
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you tend to want values of n that are 30 or greater
besides that the normal is a good approximation; but you have to account for errors that creep in as a result of equating a continuous count with a discrete count
mean = np variance = npq sd = sqrt(npq)
where q = -p
err ... 1 - p
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Because the normal approximation is not accurate for small values of n, a good rule of thumb is to use the normal approximation only if np>10 and np(1-p)>10. http://www.stat.yale.edu/Courses/1997-98/101/binom.htm
np here is about 5
thank you tha make more sense
yep
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