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OpenStudy (anonymous):
do you want this expanded?
OpenStudy (anonymous):
yes pleasei know its easy but its time consuming
OpenStudy (anonymous):
x^3+3x^2 dx + 3x dx^2 + dx^3
OpenStudy (anonymous):
dx meaning delta x
OpenStudy (anonymous):
by any chance are using the method of increments?
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OpenStudy (anonymous):
Binomial theorem.
OpenStudy (anonymous):
im finding the derivative of a funtion
OpenStudy (anonymous):
i assume the original function is x^3 right
OpenStudy (anonymous):
ah then you need to subtract x^3
OpenStudy (anonymous):
That gives you 3x^2 dx + 3x dx^2 + dx^3
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OpenStudy (anonymous):
no its x^3 + x ^2
OpenStudy (anonymous):
Then you need to divide it by dx
OpenStudy (anonymous):
3x^2 + 3 x dx + dx^2
OpenStudy (anonymous):
what now?
OpenStudy (anonymous):
And then you take the limit as dx approaches 0.
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OpenStudy (anonymous):
you know there are a couple of methods to finding the derivative basically they are all the same, but i really like this one particular one called method of increments.
OpenStudy (anonymous):
Which is in this case easy, so you are left with 3x^2 which is indeed the derivative of x^3
OpenStudy (anonymous):
your question reminded me of it :)
OpenStudy (anonymous):
I know I just explained you how to do it by increments.
OpenStudy (anonymous):
Just read what I wrote.
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OpenStudy (anonymous):
i know how to find the derivative i just wanted it to be distributed
OpenStudy (anonymous):
relax, ythenaifold, i know what you wrote, i was simply expressing my thoughts.