Question

-3x^2 + 24x

need urgent help in finding the maximum

Answer 1

max value is where
\[x=4\] plug it in and you will get your max

Answer 2

take the derivative, make it equal to zero, find x..that's ur answer

Answer 3

how did you get tat
perfect but i am puzzeled in how you got 4 for x. can you pls write in detail.

Answer 4

yes. do find the maximum or minimum of a quadratic is the same as finding the second coordinate of the vertex. the first coordinate is always
\[-\frac{b}{2a}\] and the second coordinate is whatever you get when you replace x by that value

Answer 5

in your example
\[a=-3,b=24\] so
\[\frac{-b}{2a}=4\]

Answer 6

You need to take the first derivative of the expression. Once you do that, you should get

\[-6x+24\]

Then you set that equal to 0, and solve for x.

so, \[x = 4\]

Then plug that x value back into the original equation to get the y value (max value of y).

\[-3(4^{2}) + 24(4) = 48\]

Answer 7

thank you so much!