How do you fine arccot(-sqrt(3))?
Please don't just give me an answer, I really need help with the concept which I am not understanding.

Question

amistre64 · Answer

which basic triangles, or angles have a sqrt(3) in them?

anonymous · Answer

Um... 30 60 90, right?

amistre64 · Answer

yes, then the answer has to be in that portion of form

amistre64 · Answer

the arc in front simply means that this is a ratio that comes from some angle

anonymous · Answer

Well, I know cot is adjacent/opposite... But, what do i do from there?

amistre64 · Answer

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amistre64 · Answer

first get the angle

anonymous · Answer

adj/opp is 1/sqrt(3) or sqrt(3)/3

amistre64 · Answer

cot(30) = sqrt(3)  right?

anonymous · Answer

right

amistre64 · Answer

now we have to fit it into the range of the arc function; which is either from 0 to pi or -pi/2 to pi/2

anonymous · Answer

also, how do you know which angle you are starting from? (for instance in this triangle we used 30 as angle theta)

amistre64 · Answer

i think its the pi/2 one

amistre64 · Answer

the angle is the one that matches up with the definition for the function

amistre64 · Answer

cot = adj/opp so we look for the angle that matches this cot

amistre64 · Answer

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