Question

if logb(3^b) = b/2, then b =
a. 1/9
b. 1/3
c. 1/2
d. 3
e.9
please show how to get to the solution!

Answer 1

Use opposite operations until you get to expressions you can evaluate:
GEt rid oof the log by taking to exponent of b
\[\log_{b} (3^b)=b/2\]
\[3^b=b ^{(b/2)}\]

Answer 2

Can you take it from there?