Question

find x such that the distance between (x, -10) and (-20,-5) is the square root of 425.

Answer 1

\[distance=\sqrt{(x-x1)^2+(y-y1)^2}\]

Answer 2

\[\sqrt{(x-(-20))^2+(-10-(-5))}=\sqrt{425}\]

Answer 3

425=(x+20)^2+(-5)^2

Answer 4

wait; where did you loose the squared on the (-10+5)

Answer 5

fixed lol

Answer 6

good eye

Answer 7

lol it confused me for a sec!

Answer 8

\[425=(x+20)^2+(-5)^2\]

Answer 9

it was a type-o

Answer 10

the 2 should have always been there

Answer 11

haha okay; i was just making sure!

Answer 12

until this step
\[425=(x+20)^2+25\]

Answer 13

\[400=(x+20)^2\]

Answer 14

you will get two solutions x=-20 or x=0 lol
i think i should retire for tonight

Answer 15

haha; thank you so much!