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lim as x approches infinity of (9-sinX)/(2X)
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as x gets bigger and bigger, the denominator 2x will approach infinity, but the numerator will only get as big as 10 (since 9-(-1) = 10). This is because sin(x) is bound on [-1,1] So the expression will approach zero as x approaches infinity
i think there is a way to factor out that 2x though and use the property as x approches infinity, sinx/x = 0
even then, you'll still get a limiting value of 0
you could use the squeeze theorem to show it is zero
okay thanks guys
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