If you have a number like "200" and you have the same number but with a decimal, "200." Which one has one significant figure and which has three sig. figs? (This is is more of a chemistry question, but there's no category for that :P)
a sig fig is all the figs that are needed to make a coherent discription of the number being used
So, does that mean that 200. has three significant figures while 200 only has one?
200 has 1 significant figure 200.decimal has 3 significant figures all zeros between nonzero numbers are significant figures
id say each number has 3 ... but they may have changed the terminology on me over the years :)
Ok, but then 200.0 has four sig figs right? And thanks amistre, the people I asked had the same answer
You can indicate which is the final sig fig by punctuation: place a bar over it.
well i think the convention is that 200 has only 1 significant figure. because 200 can mean 150 to 249 or 195 to 204 or 199.5 to 200.4, but I assume that it has the least number of significant figure possible, 1
Ok, thanks. So as my problem states, if I were to "Write the numbers 10, 100, and 1000 in scientific notation with two, three, and four significant figures, respectively," then would my first answer be 10. * 10^0 ?
No.
Or 1 * 10^1 ?
1x10^1
and so forth...
Wait but doesn't 1 only have one sig fig?
I'm confused >_<
1.0 x 10^1 and so on... I really found this helpful when I was stumped on sig fig: See 5:42 in http://www.khanacademy.org/video/more-on-significant-figures?playlist=Pre-algebra
Sorry about my prior typo - and good catch on your part.
This is the one he mentions at about 5:50 in the other one: http://www.khanacademy.org/video/scientific-notation-1?playlist=Algebra%20I%20Worked%20Examples
Best wishes, I need to go back to my studies.
Ahh now it's making sense, so 100 in scientific notation with 2 sig figs would be 1.00 * 10^2 right?
Yes
1.0 I think is enough.
Thanks so much I really appreciate your help!
Def check the vid I sent, it is where I learned this stuff (again after 30 years out of school).
I will. Thanks again!
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