Question

how can you tell if the points form a right triangle (2,4)(-1,6)(-3,1)??

Answer 1

use point-slope form and write out the equations for the lines.
then check to see whether any 2 lines are perpendicular with one another

Answer 2

can you use the converse of the pythagorean theorem

Answer 3

find the slope between each two points then if slope 1 * slope 2 =0 ===> the triangle is right triangle

Answer 4

site has now told me at least 20 times that amistre gave me a medal for one problem. i mean thanks and all, but enough already!

Answer 5

(2,4) (-1,6) (-3,1)
-2-4 -2-4 -2-4
------------------
0,0 -3,2 -5,-3 aint that one


(2,4) (-1,6) (-3,1)
1-6 1-6 1-6
-----------------
3,-2 0,0 -2,-5 .... aint those


(2,4) (-1,6) (-3,1)
3-1 3-1 3-1
-----------------
5,3 2,5 0,0 aint those either

Answer 6

find the distance between the points , call them a, b, c and check if
\[a^2+b^2=c^2\]

Answer 7

it keeps telling me you gave ME a medal ....

Answer 8

ive refreshed, dumped cookies, logedin and out ...

Answer 9

lol
is that firebug underneath?

Answer 10

chrome

Answer 11

if 2 lines are perpendicular with one another, the product of their slopes is -1

Answer 12

i mean underneath the web page. looks like firebug or something similar, where you can inspect the elements etc

Answer 13

dunno, it a chrome feature; ctrl shift i

Answer 14

ahhh

Answer 15

so find the slopes of each of the lines and see if you get negative reciprocal when comparing two of the line segment slopes

Answer 16

then it is a right triangle

Answer 17

i compared vector components after putting each vertix at the origin

Answer 18

but i think thats what amistre was saying above

Answer 19

amistre you find the slope weird

Answer 20

:) vectors are slopes .... so i just go for broke

Answer 21

\[\frac{4-6}{2-(-1)}=\frac{-2}{3}, \frac{4-1}{2-(-3)}=\frac{3}{5}, \frac{6-1}{-1-(-3)}=\frac{5}{2}\]
none of these are negative reciprocal of the other
so no it is not a right triangle