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(x + 2)4 = x4 + 8x3 +... Use the Binomial Theorem to complete the binomial expansion. Enter only the next three terms; use the ^ key for exponents, example: 10x^2+20x+30.
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i am solving this without binomial theorem since i don;t know much about this : (x+2)^4=((x+2)^2)^2 (x+2)^2=(x^2+2^2+2(x)(2))= x^2+4+4x (x^2+4+4x)^2=(x^2+4+4x)(x^2+4+4x) = x^4+4x^2+4x^3+4x^2+16+16x+4x^3+16x+16x^2 =x^4+4x^3+4x^3+4x^2+16x^2+4x^2+16x+16x+16 =x^4+8x^3+24x^232x+16
\[(x+2)^4=((x+2)^2)^2\] \[(x+2)^2=(x^2+2^2+2(x)(2))= x^2+4+4x \] \[(x^2+4+4x)^2=(x^2+4+4x)(x^2+4+4x) \] \[x^4+4x^2+4x^3+4x^2+16+16x+4x^3+16x+16x^2\] \[x^4+4x^3+4x^3+4x^2+16x^2+4x^2+16x+16x+16\] \[x^4+8x^3+24x^232x+16\]
got it bonita the answer is \[x^4+8x^3+32x+16\]
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