The roots of 2k^2 + 6 = x^2 + 8x are equal.. How do I solve for k? :( Thanks!
solve for roots of one side so roots of (x^2+8x) are x(x+8) so they are x1=0 and x=-8
but how will I solve for k if I don't know x? :(
w8 a sec....were they under sqr?
the original wasn't under a square root
then tht's not right
no angela, by roots they meant x(x+8) x=0 and x=-8
yea Lana...i misunderstood it ;/
:D but ur answer was right
oops ;/
lols
I'm lost sorry :(
x^2+8x-((2k^2)+6), then apply the quadratic formula with a=1, b=8, c=-((2k^2)+6), assuming k is just a constant
The answer is 11/6.. I just don't know how it happened. :(
sorry i was wrong but there is something fishy about this problem...
It's okay :) Thanks anyway!
Dimsy, what is variable in this case (x or k) ?
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