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Mathematics 8 Online
OpenStudy (anonymous):

The roots of 2k^2 + 6 = x^2 + 8x are equal.. How do I solve for k? :( Thanks!

OpenStudy (anonymous):

solve for roots of one side so roots of (x^2+8x) are x(x+8) so they are x1=0 and x=-8

OpenStudy (anonymous):

but how will I solve for k if I don't know x? :(

OpenStudy (angela210793):

w8 a sec....were they under sqr?

OpenStudy (anonymous):

the original wasn't under a square root

OpenStudy (angela210793):

then tht's not right

OpenStudy (lalaly):

no angela, by roots they meant x(x+8) x=0 and x=-8

OpenStudy (angela210793):

yea Lana...i misunderstood it ;/

OpenStudy (lalaly):

:D but ur answer was right

OpenStudy (angela210793):

oops ;/

OpenStudy (lalaly):

lols

OpenStudy (anonymous):

I'm lost sorry :(

OpenStudy (anonymous):

x^2+8x-((2k^2)+6), then apply the quadratic formula with a=1, b=8, c=-((2k^2)+6), assuming k is just a constant

OpenStudy (anonymous):

The answer is 11/6.. I just don't know how it happened. :(

OpenStudy (anonymous):

sorry i was wrong but there is something fishy about this problem...

OpenStudy (anonymous):

It's okay :) Thanks anyway!

OpenStudy (nikvist):

Dimsy, what is variable in this case (x or k) ?

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