Question

the acceleration of an equipped with a standard engine is:
a = f(t) = 4 + .08t (0≤t≤12)
t seconds after starting from rest at full throttle.
The acceleration of an engine equipped with a turbo-charger is given by
a = g(t) = 4 + 1.2t + 0.03t² (0≤t≤12).
how much faster is the turbo charged model moving than the model with the standard engine at the end of a 10-sec test run at full throttle?

Answer 1

x= double integral of a= (2t^2)+(.08/6)t^(3), standard engine
x=(2t^2)+(1.2/6)t^(3)+(.03/12)t^(4), turbocharged engine
after 10 seconds find which engine went further by letting t=10 in these equations so..
x=(400)+(80/6)=413.3, standard engine
x=(400)+(200)+(300/12)=625, turbocharged engine

Answer 2

let me know if this helped...

Answer 3

okay I am going to look over it at 10 AM when I have free time. How did you find the first part though?

Answer 4

if u integrate acceleration twice you can get the displacement...