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secx-cosx/tanx=___? Explain pls
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do u mean (secx-cosx)/(tanx) or secx-(cosx/tanx) ??
the first one. (secx-cosx)/tanx
|dw:1316242561892:dw|
how did it become sin*2x?
its a property. 1-cos^2x=sin^2x
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|dw:1316242936486:dw|
pythagorean i believe
if it was just (sec(x)-cos(x))/tan(x) then it will be : ((1-cos^2(x))/cos(x))/tan(x) =sin^2(x)/sin(x) =sin(x) --------------------------------------- if it was sec(x)-(cos(x)/tan(x)) then : sec(x)-(cos^2(x)/sin(x)) =sec(x)-((1-sin^2(x))/sin(x)) =sec(x)-cosec(x)-sin(x)
so duz it help?
why did you multiply sin^2x/cos^2 by cosx/sinx?
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first of all, tanx=sinx/cosx. multiply by the reciprocal, cosx/sinx
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