If 4^2-x=3, then 4^2x-1=? Step by step solutions pls
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OpenStudy (anonymous):
4^2-x=3
16-x=3
x=13
4^2 (13)-1=x
208-1=x
x=207
OpenStudy (anonymous):
\[4^{2}-x = 3\]\[16-x = 3\]\[-x = -13\]\[x=13\]Then just plug in x into the 2nd equation and solve:\[4^{2 \times 13} - 1 = y\]\[4503599627370495 = \]
OpenStudy (anonymous):
y
OpenStudy (anonymous):
oh sorry i misread the question
OpenStudy (anonymous):
Your answer seems a lot less "out there." I solved the question that was posted, but the question was probably formatted incorrectly, so you're probably right.
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OpenStudy (anonymous):
is it 4^(2-x) or (4^2)-x
OpenStudy (anonymous):
uh huh thankx
OpenStudy (anonymous):
then alex is right
OpenStudy (anonymous):
if the equation was 4^(2-x)=3 then :
(4^(2-x))^2=3^2
4^(4-2x)=9
4^4=9*4^2x
4^3=9*4^(2x-1)
4^(2x-1)=64/9
OpenStudy (anonymous):
why did you square the 4^(2-x) and the 3? but you got the right answer.
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OpenStudy (anonymous):
If 4^2-x=3, then 4^2x-1=? Step by step solutions pls
\[4^2-x=3\]
\[16-x=3\]
\[-x=3-16\]
\[-x=-13\]
\[x=13\]\[4^2x-1=16(13)-1=207\]