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A revenue function is given by R(x)=15+114x-3x^2, where x is the number of units produced and sold. Find the value of x for which the revenue is maximum.
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thats if the derivetive is zero
this one is simple, just find the derivative of of the revenue function and then get the critical points
\[R(x)\prime = -6x + 114\] \[x = 114/6\] x=19
thanks
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