A buoy in the harbor of san juan,puerto rico, bobs up and down.The distance between the highest and lowest point is 3 feet.It moves from its highest point down to its lowest point and back to its highest point every 8 seconds. a)Find the equation of the motion for the buoy assuming that it is at its equilibrium point at t=0 and the buoy is on its way down at that time. b)Determine the height of the buoy at 3 seconds. c)Determine the height of the buoy at 12 seconds.
http://www.freemathhelp.com/forum/archive/index.php/t-68685.html?s=81349e7c156e89af0e48100743b7ef6d
Nancy Lam u must see this link hope u would get it soon
I did see,but I still don't know answer
this one is good then the previous one
a) 3cospi/4 ?
f(t)=1.5*sin(pi*t/4) f(3)=1.06 feet f(12)=1.5sin(pi)=0
Noureldin amplitude is 1.5?
I don't get ,go up 3 and go down 3 or 3 include up and down ?
1.5 up and 1.5 down = 3 ?
thank your guy Can some one help me one more \[y=-3\sin\frac{\pi}{2}\theta\] my answer: is period = 4, I positive correct but don't know how to graph
I don't get 4 is period how much degree ?
thank kushashwa23
my pleasure Nancy Lam
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