Question

If 4^(2-x)=3 then 4^(2x-1)=?

Answer 1

-x + 2 = log_4(3)
2x - 1 = log_4(?)
x + 1 = log_4(3*?)
3*? = 4^(x+1)
? = (4^(x+1))/3

Answer 2

should be a way to cancel x 1 minute

Answer 3

-2x + 4 = log_4(9)
2x - 1 = log_4(y)
3 = log_4(9y)

9y = 64
y = 64/9

Answer 4

http://www.wolframalpha.com/input/?i=4^%282-x%29%3D3+%2C++4^%282x-1%29

Answer 5

how do you know where to add the log?

Answer 6

which part?

Answer 7

pls explain this part futher: -2x + 4 = log_4(9) 2x - 1 = log_4(y) 3 = log_4(9y)

Answer 8

(4^(2-x))^2=3^2
4^(4-2x)=9
4^4=9*4^2x
4^3=9*4^(2x-1)
4^(2x-1)=64/9