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what is the phase shift of y= 3cos(6x+ pi/2)
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pi/2
be careful here
if you want to read the phase shift from the formula it needs to look like \[A\cos(B(x-c))\] not \[A\cos(Bx -c)\]
if you really want to graph this thing it is the same as \[-3\sin(6x)\] which it a lot easier to figure out. but to find the phase shift you will need to write it as \[3\cos(6(x+\frac{\pi}{12})\]
so it would be \[\Pi/12\]
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yes
thank you
yw
but i repeat it would be much easier to graph \[y=-3\sin(6x)\] where the amplitude is 3 and the period is \[\frac{\pi}{3}\]
then to try to figure out what this looks like from the period and the phase shift.
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