Question

limit as x approaches 2 from the left hand side for the following function
[(x-27)(x-91)]/(x^2 + 4x + 4)

Answer 1

\[\lim_{x \to 2^-} \frac{(x-27)(x-91)}{x^2+4x+4}\]
then just plug in the value 2 and see where it gets you
\[\lim_{x \to 2^-} \frac{(2-27)(2-91)}{2^2+4*2+4}\]
\[\lim_{x \to 2^-} \frac{(-25)(-89)}{16}\]
\[\lim_{x \to 2^-} \frac{2225}{16}\]
\[\lim_{x \to 2^-} \frac{2225}{16} = 139.0625\]