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Show that e^(-2ln5) = -25
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I understand that -2ln(5) = ln (5^-2), but I'm stuck from here.
sorry, I mistyped the question. "Show that e^(-2ln5) = 1/25" not -25.
e^ ln (5^-2) = 5^-2 ( by definition)
5^-2 = 1/25
Why is e^ ln (5^-2) = 5^-2 ?
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because ln = log to the base e
it might help to consider logs to the base 10 log _10 100 = 2 because 10^2 = 100 therefore, substituting 2 = log _10 100 in 10^2 = 100: 10 ^ (log_10 100) = 100
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