In 1960, the life expectancy in the UK was 71.1 years. In 2008, it was 79.9 years. Let F(t) = life expectancy and t = the number of years since 1960. a) Find a linear function that fits the data. b) Use the function of Part (a) to estimate the life expectancy in 2010. Show your work not just the final answer.
You just top posted, but you're not the only one. I gave you all the clues you needed. Post what I wrote again and I'll help you more.
So ... a linear function is of the form f(x) = mx + c. Draw a graph with the data in this problem: you have two points (x,y) = (1960, 71.1) and (x,y) = (2008,79.9) Now get a ruler and draw the straight line through these points. What is the slope of this curve m? Now solve for c. Can you do that much?
lol yes i can thank you
Tell me what values of m and c you get.
i got 8.8 and 48
i did y2-y1 over x2-x1
That's correct in principle, but you have made some sort of error (y2-y1)/(x2-x1) = (79.9 - 71.1)/(2008-1960) = .... NOT 8.8 but ...
9?
Seriously? Cmon. Do the math.
m = (y2-y1)/(x2-x1) = (79.9 - 71.1)/(2008-1960) = 8.8/48 = 0.1833. Now, solve for c.
oh i c. I was skipping a step...but i do not know hwo to solve for c, that is why i am here
f(x) = mx + c. So c = f(x) - mx for all x. Take x = 1960. Then f(x) = 71.1 and hence c = f(x) - mx = ....
if i am adding i got 2031
or 1888
Look at the formula and substitute: c = f(x) - mx = 71.1 - (0.1833)x(1960) = 71.1 - 359.3 = -288.3 This means you now know the linear function f(x) = mx + c, as you know both m and c. Clear?
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