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evaluate the limit as x -> +,-infinity: q(x)=-2x^3+3x^2-12
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Just looking at the leading term -2x^3, when x --> inf, -2x^3 --> -inf, we can see this if we plug in some large positive number for x The other terms factor in, but as x gets larger and larger, their influence diminishes. So as x --> inf, q(x) --> -inf -------------------------------------------------------------------- Using the same logic, as x --> -inf, q(x) --> inf
so the answer is -inf?
which limit are you referring to? as x --> inf or x --> -inf ?
both... right?
the answers vary, you cannot evaluate the limit as x goes to BOTH +inf and -inf
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this is a two part problem
ok so im going to get two seperate answer for this problem?
yes
ok thank you
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