Find an equation for the line that is perpendicular to y=4x-5. and passes through (5, -2)

Question

anonymous · Answer

the slope of the line = -1/m where m is the slope of your line
use the general form
y-y1 =m(x-x1)   where x1 y1 is the point on the line and m is the slope you have just found

anonymous · Answer

does that help?

anonymous · Answer

do you know the slope of the line y = 4x - 5?

anonymous · Answer

4x

anonymous · Answer

4 is the slope - the coefficient of x  ( ie number that multiplies x)

anonymous · Answer

so slope of perpendicular line = -1/4

anonymous · Answer

now plug in  -1/4 and (5,-2) into the general equation and you've got it

anonymous · Answer

-1/4x-3?

anonymous · Answer

where is y?

anonymous · Answer

y-y1 = (-1/4) (x-x1)  is the equation you need to use

what values go in for x1 and x1?

anonymous · Answer

5?

anonymous · Answer

yes x1 = 5 and i meant x1 and y1 - what is the value for y1?

anonymous · Answer

we are given the point (5,-2) which is on the line 
so (x1,y1) =( 5,?)

anonymous · Answer

-2

anonymous · Answer

right so plug x1=5 and y1 = -2 into the equation and we have the answer

anonymous · Answer

y - 5 = (-1/4)(x - (-2))

anonymous · Answer

this can be simplified further

anonymous · Answer

thats where i got stuck,