Question

write an equation of the line containing the given point and parallel to the given line. (2,-1);2x-9y=8

Answer 1

m = 2/9
y - 1 = 2/9(x-2)
9y-9 = 2x - 4
2x - 9y + 5 = 0

Answer 2

y=(2/9)x+13/9

Answer 3

2x - 9y=8
-9y = 8 - 2x
9y = 2x - 8
y = 2x/9 - 8/9
slope = 2/9
y-intercept = -8/9

ynew = slope*x + b2
ynew(2) = -1 = 2(2)/9 - b2,
where b2 is y-intercept of parallel line going through point (2,-1)
b2 = 4/9 + 1
= (4 + 9)/9
= 13/9

Ans. ynew = 2x/9 + 13/9

Answer 4

the slope is m=2/9
then sub x=2, y=-1 and m=2/9 into y=mx+b to get b
-1=(2/9)(2)+b
-1=4/9 + b
b=-13/9
now just sub b=-13/9 and m=2/9 into y=mx+b
y=(2/9)x-13/9

Answer 5

Note b2 is -13/9 not 13/9.

Answer 6

thank you all for your help

Answer 7

woops my answer is wrong then xD

Answer 8

@mimi you made a sign error on the LHS of point-slope: y-(-1)

Answer 9

oh yeah woops my bad, so~ sleepy xD