Java Question:

I have editable JTextFields in my code. The JTextField is initialized with a value of "" using .setText(). I have code to check the value of the JTextField to avoid a null value, i.e. the user has to change it but it would appear to not be working. I am going to paste the chek part to see if it's something obvious. If needed I can attach the whole thing:

if (empNameText.getText() == null)
{
setTextRed(empNameLabel);
goodData = false;
System.out.println("True");
}
else
{
System.out.println("False");
}

Keep in mind I have the System.out in the

Question

Java Question:

I have editable JTextFields in my code. The JTextField is initialized with a value of "" using .setText(). I have code to check the value of the JTextField to avoid a null value, i.e. the user has to change it but it would appear to not be working. I am going to paste the chek part to see if it's something obvious. If needed I can attach the whole thing:

if (empNameText.getText() == null)
			{
				setTextRed(empNameLabel);
				goodData = false;
				System.out.println("True");
			}
			else
			{
				System.out.println("False");
			}

Keep in mind I have the System.out in the

anonymous · Answer

The system.out is included for troubleshooting purposes.

anonymous · Answer

Allow me to kick myself. Since I am using a string I need to use .equals or I am looking at the memory address of the variable. Found my answer here: http://www.codingforums.com/archive/index.php/t-96034.html

anonymous · Answer

Yeah, you're gonna want to use the .equals method of the string class for this, as apposed to the ==.

anonymous · Answer

I got confused since I was working with a single character string. While I knew I was dealing with a string my brain kept screaming char. It's always the easy problems that kick your retrice:)

anonymous · Answer

Well really an empty string, but I kept thinking char.

anonymous · Answer

Haha, quite alright.