Question

If you were to use the substitution method to solve the following system, choose the new system of equations that would result if z was isolated in the first equation.

2x – 5y + z = 15
4x – y + 3z = 15
3x – 2y + 2z = 13

Answer 1

1) z = 15 - 2x + 5y

which would result in
2)
4x -y + 3(15 -2x +5y) = 15
4x -y + 45 -6x + 15y = 15
-2x +14y = -30
3)
3x -2y +2(15 - 2x +5y) = 13
3x - 2y + 30 - 4x + 10y = 13
-x +8y = -17

Answer 2

which is the answer

Answer 3

these are the answers given to choose from


–2x + 14y = –30
–x + 8y = –17

10x – 16y = –30
7x – 12y = –15

–18x – 14z = –60
–5x + 8z = 43

22x + 16z = 90
11x + 8z = 43

Answer 4

hey can u please help me understand what u just wrote

Answer 5

there i answered