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Determine whether the function is one-to-one. f(x)= x^(4)+5, 0<=x<=2
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one to one function
most polynomials are
yep
in order to solve this put 0 1 and 2 into the equation and solve if you get different y values then it is one to one
you need to show f(a)=f(b) => a=b, so put a^4 +5 = b^4+5 => a^4 = b^4, since 0<=x<=2 => a=b, so your function is 1-1. Note however, if your domain did not force x to be between 0 and 2, this function would not be 1-1.
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