Question

Determine the stopping distances for a car with an initial speed of 95 km/h and human reaction time of 1.0 s for the following accelerations.

Answer 1

\[(348/abs(a))meter+26.38meter=\Delta x\]

Answer 2

since the reaction time is 1s, there wont be any change in velocity during this second

distance travelled i this second = initial speed * time

initial speed= 95 km/h = 95 * 5 / 18= 26.388 m/s

after that time the acceleration begins.

so u can use the equation v^2 - u^2 = 2*a*s

in this equation u consider

v= 0
u= 26.388 m/s
a = value of acceleration
then u will get the value of s

then the total stopping distance will be =
(distance travelled in reaction time) + s

so u can substitute the values
i will do it if u give me the values of acceleration

Answer 3

am i right?