Question

bx-a=5a+c solve for x

Answer 1

\[\Large bx-a=5a+c\]


\[\Large bx=5a+c+a\]


\[\Large bx=6a+c\]


\[\Large x=\frac{6a+c}{b}\]

Answer 2

thank you !

Answer 3

add "a" to both sides like this \[bx = 5a +c +a\] add like terms \[bx = 6a + c\] divide by "b" \[x = 6a + c \div b\]

Answer 4

better to write \[x = (6a+c)\div b\] to make it clear that the entire quantity (6a+c) is divided by b

Answer 5

Hey Jim how do you write the equation where it puts the denominator like the way you did.. ???

Answer 6

type x=\frac{6a+c}{b}

Answer 7

\frac{ allows for stuff like \[\Large \frac{x+y}{z}\]

Answer 8

oh ok.. Thanks