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Solve the following equation: 1/x+2/(x-1)=3
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He doesn't need the answer; he needs detailed steps
Thanks james
then myininaya will write it out
first of all we do not want x=0 or x=1 anyways ... multiply both sides by x(x-1) to clear the bottoms \[x(x-1)\frac{1}{x}+x(x-1)\frac{2}{x-1}=x(x-1)3\] \[(x-1)+2x=3x(x-1)\]
we will use the distributive property on the right hand side \[(x-1)+2x=3x^2-3x\] combine like terms on left hand side \[3x-1=3x^2-3x\] put everything on one side
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\[3x^2-3x-3x+1=0\]
\[3x^2-6x+1=0\]
Thank you
np
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