What is the slope of the line that passes through (1, 4) and (1, –3)? I got 7/0. That would mean it's 0? Or undefined?
that is right. but we canot divide by zero.
it is -7/0
undefined
it is also -7/0
So wait, it's undefined?
no specific answer, like that. cannot solve, or syntax error. or math error.
that is correct. the line is undefined
the slope is defined, its just that the number produced, if viewed solely as a number is undefined. The slope is a vertical slope
hey the answer is here the slope of the line is -7/0 so it is infinite so it is a line parallel to y-axis. because slope of a line = tan ( angle made by lione with x) for a line parallel to y the slope = tan 90 = infinite
abhinav is right.
lorda mercy here we go again. it is not "infinite" it is just not a number
but he is right that it is paralel to the y-axis.
the slope measures something. it tells you how many units up or down in the y direction the line travels as it travels one unit in the x - direction
hey anything anything divided by zero is considered as infinite dont u know that?
since a vertical line does not travel one unit in the x - direction, the question makes no sense and so there is no slope. like asking what is the gas mileage for my bicycle.
really? yes i don't know it because it is not true
even as a limit statement it is not true
if some math teacher told you that please tell them that they are sadly mistaken
hey dont give silly explanations what do you think i the slope of any line parallel to y axis dont u know that slope = tan (theta
well if the slope is a number then it would be \[\tan(\theta)\] yes, but if \[\theta=\frac{\pi}{2}\] then \[\tan(\frac{\pi}{2})\] is not a number since \[\frac{\pi}{2}\] is not in the domain of tangent
the slope has a specific meaning, as it measures something. if there is nothing to measure then it does not have a meaning
ok so u say there is no slope for any line parallel to y axis?
and if you were told that \[\tan(\frac{\pi}{2})=\infty\] you were told incorrectly. even as a limit this is not true
as fas as i know the slope is infinite if it is parallel to y-axis and 0 if it is parallel to x-axis.
far*
Listen to satellite73. He is exactly right. The limit \[\lim_{x \rightarrow \pi/2} \tan x \] does not exist, so it makes absolutely no sense to assign a value to tan(pi/2)
by which i mean \[\lim_{x\rightarrow \frac{\pi}{2}^+}\tan(x)=-\infty\] whereas \[\lim_{x\rightarrow \frac{\pi}{2}^-}\tan(x)=\infty\]
ok if u dont agree with me then u can go with ur own explanation idont want to fight with u . u are not even thinking about my explanation
i wonder where this idea comes from that the symbol \[\frac{a}{0}\]is somehow infinity. i assure you that it is not
abhinav, your explanation is not sound; you say that the slope is infinite, which means that it moves an infinite amount when x moves, but x never moves
satellite in some aspects it is undefined and in some aspects it is infinite.
i have a cliff that is 3 feet high, what is its slope? infinity? no
@abh ... Let us suppose for a moment that a/0 = inf Then what is 2a/0 - a/0 ? Is it inf - inf = 0? or is it 2inf - inf = inf? or is it inf - inf = inf? You just can't make this definition consistent.
i do believe some math teacher may have told you this, and therefore it is in no way a fault or failing on your part. just goes to show that you should not believe everything a math teacher says.
i vertical line has no slope that can be defined numerically; its simply a vertical slope
of course inf -inf = inft because you will goin to subtract infintly.
and 2inf is still inf :))
actually the question says That would mean it's 0? Or undefined? so at least this math teacher knows something undefined is the correct answer
if you believe \[\frac{1}{0}=\text{something}\] the presumably i can solve \[1=0\times \text{something}\] a miracle if ever there was one
ok if u think the slope if undefined then u can go to the international maths research centre
ok hope this will provide a correct answer since the slope of a line parallel to y axis is undefined, and 7/0 is also undefined its is a line parallel to y axis. i feel may be u are right. i am sorry for my arguement against u
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