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Mathematics 15 Online
OpenStudy (anonymous):

Vertical asymptotes of (x^2-4)/(x^3+2x^2+x+2)

OpenStudy (anonymous):

set denom equal to 0 and those are your vertical asymptotes. THese are the values which x can NOT be.

OpenStudy (anonymous):

I dont think i did it right

OpenStudy (anonymous):

because 0 doesnt make the denominator equal to 0

OpenStudy (anonymous):

It has three solutions \[(x+2)(x^2 + 1)\] solutions are: \[x=-2, x=\pm i\]

OpenStudy (anonymous):

yeah that looks right.. i was getting imaginary numbers too.

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