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Mathematics 8 Online
OpenStudy (anonymous):

In the figure below, if the length of AB is 10, find the length of AD

OpenStudy (anonymous):

use the pythagorean theorm i think..what kind of figure is it?

OpenStudy (anonymous):

|dw:1316705744526:dw|

OpenStudy (anonymous):

whats that heartish shape, like after 10?

OpenStudy (anonymous):

i found AC only....no AED is a triangle and ACB is inside of it

OpenStudy (anonymous):

hmm i did this last year, wats AE

OpenStudy (anonymous):

AE is not given... AB=10, CB=8 and ED=10

OpenStudy (anonymous):

AC is 6 rite?

OpenStudy (anonymous):

yap

OpenStudy (anonymous):

the answer is 25/2 but i cant figure out how

OpenStudy (anonymous):

OMG wait i think noe, wait i have to get ma last year notes...

OpenStudy (anonymous):

k

OpenStudy (anonymous):

figured it out myself :P

OpenStudy (anonymous):

kk...there are special triangles: there are 45-45-90 triangles ( right triangles) they have rules: if you want to find their hyp i is the squareroot of two times on of the legs (45) then there are 30-60-90 (also rite triangles) their rules: to find the long leg, it is the squarroot of three times the short leg to find the hyp, you must multiply the short leg by 2 HOPE THIS HELPS!!!

OpenStudy (anonymous):

oh..

OpenStudy (anonymous):

there is actually another formula for it..forget the name but this is how it goes.... CB/ED = AB/AD

OpenStudy (anonymous):

therefore 8/10=10/AD..which gives me 25/2

OpenStudy (anonymous):

ohh thanks i will try to remeber it as a reference..YOU LEARN A NEW THING EVERYDAY!!;)

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