In the figure below, if the length of AB is 10, find the length of AD
use the pythagorean theorm i think..what kind of figure is it?
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whats that heartish shape, like after 10?
i found AC only....no AED is a triangle and ACB is inside of it
hmm i did this last year, wats AE
AE is not given... AB=10, CB=8 and ED=10
AC is 6 rite?
yap
the answer is 25/2 but i cant figure out how
OMG wait i think noe, wait i have to get ma last year notes...
k
figured it out myself :P
kk...there are special triangles: there are 45-45-90 triangles ( right triangles) they have rules: if you want to find their hyp i is the squareroot of two times on of the legs (45) then there are 30-60-90 (also rite triangles) their rules: to find the long leg, it is the squarroot of three times the short leg to find the hyp, you must multiply the short leg by 2 HOPE THIS HELPS!!!
oh..
there is actually another formula for it..forget the name but this is how it goes.... CB/ED = AB/AD
therefore 8/10=10/AD..which gives me 25/2
ohh thanks i will try to remeber it as a reference..YOU LEARN A NEW THING EVERYDAY!!;)
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