Question

quadratic equations how do you solve 2x^2+1=5

Answer 1

first bring it to this form:

ax^2+bx+c=0

Answer 2

and determine what
a=?
b=?
c=?

Answer 3

okay so 2x^2-5+1?

Answer 4

i mean 5x

Answer 5

oh. so it's
2x^2-5x+1=0
?

Answer 6

yes

Answer 7

ok - so what are:
a=?
b=?
c=?

Answer 8

a=2..b=-5 c=1...right?

Answer 9

yes, correct !

Answer 10

next, we want to calculate a special number, called the discriminant.

b^2-4ac

can you do it ?

Answer 11

yeah.its 23.

Answer 12

how did you get that ?

Answer 13

just kidding.sorry.uh its 17.i forgot to multiply 2 by 4.

Answer 14

OK, you found that the discriminant is:

\[\Delta=17\]

Now, the quadratic formula is this:

\[x=\frac{-b \pm \sqrt{\Delta}}{2a}\]

Answer 15

and you already know the discriminant

Answer 16

thanks .i figured it out.

Answer 17

so what two answers did you get ?