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Mathematics 21 Online
OpenStudy (anonymous):

-3(2r-4) greater than or equal to 2 (5-3r)

jimthompson5910 (jim_thompson5910):

\[\Large -3(2r-4)\ge2(5-3r) \] \[\Large -6r+12\ge10-6r \] \[\Large -6r\ge10-6r-12 \] \[\Large -6r+6r\ge10-12 \] \[\Large 0r\ge10-12 \] \[\Large 0r\ge-2 \] \[\Large 0\ge-2 \] Since the last inequality is ALWAYS true, this means that there are an infinite number of solutions.

OpenStudy (anonymous):

thanks.

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