find the volume of the solid generated by rotating the region bounded by y= cos x, y=0, x=0, and x= pi/2 about y-axis
|dw:1316776006177:dw|
are you told to use a specific method?
slice,disk, washer........
I don't think you can get an exact answer.
I think you can only set up an integral and approximate it by simpsons or trapeziodal rule.
V= pi integral x^2 dy
please help i really dont know this
\[ V= \pi \int\limits_{0}^{1} (\cos^{-1} (y) )^2 dy\]
You can't evaluate it exactly. All you can do is approximate it. Probably use simpsons rule with 5 function values, should give a pretty good answer.
that;s if it was about the x axis.
it says about y axis.
sorry ... need my morning coffee
maybe the asker made a typo.
But even so, this integral is doable. Use integration by parts twice. First time with u' = 1, v = arccos^2(x). Remember that (d/dx)(arccos x) = -1/sqrt(1-x^2)
how do you rotate the y=cos x about y-axis?
i think its washer if you rotate it about y-axis
It is disk method if you rotate it about x or y axis
Join our real-time social learning platform and learn together with your friends!