Factor the trinomial 2x^2 + 17x - 9 on your paper. Which of the following would be part of the factored answer? (2x + 1) (2x - 1) (x - 9) none of the above
(2x-1)(x+9)= 2x2 +18x -x -9 - so from this result that 2x-1 can being from what you have wrote there
This may be a bit exhaustive, but let me know if it helps. When the coefficient of x^2 is not one, then you must multiple the first and last numbers together (-18). Once you have this number, you need to find two factors of the new number (-18) whose difference (or sum) equals the middle number (+17). In this case, +18 plus -1 equals +17. So the middle term (+17x) needs to be split up into two new terms (+18x) and (-1x). Once you have these split up, then you can begin factor by grouping. Factor by Grouping: 2x^2+18x-1x-9 Take the first two terms and find the Greatest Common Factor (GCF). It is 2x. Factor this value out. 2x(x+9) Now take the second two terms and factor out the GCF. -1(x+9) Now the expression looks like 2x(x+9)-1(x+9). In each product there is an (x+9) in common that can also be factored out, leaving the 2x and the -1. = (x+9)(2x-1)
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